# Line slope calculator x-5y=-15

**Straight line given by points A[0; 3] and B[5; 4]**

## Calculation:

**Slope-intercept form of line:**y = 0.2x+3

**Canonical form of the line equation:**x-5y+15 = 0

**Parametric form of the line equation:**

x = 5t

y = t+3 ; t ∈ R

**Slope:**m = 0.2

**Slope angle of line: φ =**11°18'36″ = 0.1974 rad

**X intercept:**x

_{0}= -15

**Y intercept:**y

_{0}= q = 3

**Distance line from the origin:**d

_{0}= 2.9417

**The length of the segment AB: |AB| =**5.099

**Vector: AB =**(5; 1)

**Normal vector: n =**(1; -5)

**Midpoint of the segment AB: M =**[2.5; 3.5]

**Perpendicular Bisector equation:**5x+y-16 = 0

**Vector OA = (0; 3) ; |OA| = 3**

**Vector OB = (5; 4) ; |OB| = 6.4031**

**Scalar product OA .OB = 12**

**Angle ∠ AOB = 51°20'25″ = 0.8961 rad**